Add support for customizing default Taskfile name via TASKFILE_DEFAULT_NAME environment variable

init.go

@@ -9,11 +9,22 @@ import (
 	"github.com/go-task/task/v3/taskfile"
 )
 
-const defaultFilename = "Taskfile.yml"
+var defaultFilename = "Taskfile.yml"
+
+// SetDefaultFilename sets the default filename for testing purposes.
+func SetDefaultFilename(name string) {
+	defaultFilename = name
+}
 
 //go:embed taskfile/templates/default.yml
 var DefaultTaskfile string
 
+func init() {
+	if name := os.Getenv("TASKFILE_DEFAULT_NAME"); name != "" {
+		defaultFilename = name
+	}
+}
+
 // InitTaskfile creates a new Taskfile at path.
 //
 // path can be either a file path or a directory path.

init_test.go

@@ -30,6 +30,37 @@ func TestInitDir(t *testing.T) {
 	_ = os.Remove(file)
 }
 
+func TestInitDirWithCustomDefaultName(t *testing.T) {
+	const dir = "testdata/init"
+
+	// Set environment variable before running the test
+	t.Setenv("TASKFILE_DEFAULT_NAME", "Taskfile.yaml")
+
+	file := filepathext.SmartJoin(dir, "Taskfile.yaml")
+	defaultFile := filepathext.SmartJoin(dir, "Taskfile.yml")
+
+	// Clean up any existing files
+	_ = os.Remove(file)
+	_ = os.Remove(defaultFile)
+	if _, err := os.Stat(file); err == nil {
+		t.Errorf("Taskfile.yaml should not exist")
+	}
+
+	// Manually call init logic
+	task.SetDefaultFilename("Taskfile.yaml")
+	defer task.SetDefaultFilename("Taskfile.yml")
+
+	if _, err := task.InitTaskfile(dir); err != nil {
+		t.Error(err)
+	}
+
+	if _, err := os.Stat(file); err != nil {
+		t.Errorf("Taskfile.yaml should exist")
+	}
+
+	_ = os.Remove(file)
+}
+
 func TestInitFile(t *testing.T) {
 	t.Parallel()